解决列表定义中linux下无法使用格式化函数的bug
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@@ -98,6 +98,21 @@ function get_username($uid = 0) {
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return $name;
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}
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/**
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* 根据用户ID获取昵称
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* @param integer $uid 用户ID
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* @return string 用户名
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*/
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function get_nickname($uid = 0) {
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static $list;
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if (!($uid && is_numeric($uid))) {
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//获取当前登录用户名
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return session('userInfo.nickname');
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}
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$name = Member::where('uid', $uid)->value('nickname');
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return $name ? $name : '未知';
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}
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function avatar($uid, $size = 'middle') {
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return request()->domain() . '/static/common/images/default_avatar_' . $size . '.jpg';
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}
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