解决列表定义中linux下无法使用格式化函数的bug

app/common.php

@@ -98,6 +98,21 @@ function get_username($uid = 0) {
 	return $name;
 }
 
+/**
+ * 根据用户ID获取昵称
+ * @param  integer $uid 用户ID
+ * @return string       用户名
+ */
+function get_nickname($uid = 0) {
+	static $list;
+	if (!($uid && is_numeric($uid))) {
+		//获取当前登录用户名
+		return session('userInfo.nickname');
+	}
+	$name = Member::where('uid', $uid)->value('nickname');
+	return $name ? $name : '未知';
+}
+
 function avatar($uid, $size = 'middle') {
 	return request()->domain() . '/static/common/images/default_avatar_' . $size . '.jpg';
 }

app/controller/admin/Content.php

@@ -45,9 +45,7 @@ class Content extends Base {
 			$map[] = ['title', 'LIKE', '%'.$param['keyword'].'%'];
 		}
 
-		$list = $this->model->where($map)->order($order)->paginate($this->modelInfo['list_row'], false, array(
-			'query' => $this->request->param(),
-		));
+		$list = $this->model->where($map)->order($order)->paginate($this->request->pageConfig);
 
 		$this->data = array(
 			'grid' => $this->modelInfo['grid_list'],

app/model/Form.php

@@ -94,7 +94,7 @@ class Form extends \think\Model {
 				$list[$field] = ['field' => $field, 'title' => $title];
 				if (strrpos($title, "|")) {
 					$title = explode("|", $title);
-					$list[$field] = ['field' => $field, 'title' => $title[0], 'format' => $title[1]];
+					$list[$field] = ['field' => $field, 'title' => $title[0], 'format' => trim($title[1])];
 				}
 			}
 		}

app/model/Model.php

@@ -123,7 +123,7 @@ class Model extends \think\Model{
 				$list[$field] = ['field' => $field, 'title' => $title];
 				if (strrpos($title, "|")) {
 					$title = explode("|", $title);
-					$list[$field] = ['field' => $field, 'title' => $title[0], 'format' => $title[1]];
+					$list[$field] = ['field' => $field, 'title' => $title[0], 'format' => trim($title[1])];
 				}
 			}
 		}